HackerRank C++ Class Template Specialization

You are given a main function which reads the enumeration values for two different types as input, then prints out the corresponding enumeration names. Write a class template that can provide the names of the enumeration values for both types. If the enumeration value is not valid, then print unknown.

#include <iostream>
using namespace std;
enum class Fruit { apple, orange, pear };
enum class Color { red, green, orange };

template <typename T> struct Traits;

// Define specializations for the Traits class template here.

template <> 
struct Traits<Fruit>{
    static string name(int index){
        switch(index){
                case 0:return "apple";
                case 1: return "orange" ;
                case 2: return "pear";
        }  
        return "unknown";
    } 
};
template <> 
struct Traits<Color>{
    static string name(int index){
        switch(index){
                case 0:return "red";
                case 1: return "green" ;
                case 2: return "orange";           
        }
        return "unknown";  
    } 
};

int main()
{
	int t = 0; std::cin >> t;

    for (int i=0; i!=t; ++i) {
        int index1; std::cin >> index1;
        int index2; std::cin >> index2;
        cout << Traits<Color>::name(index1) << " ";
        cout << Traits<Fruit>::name(index2) << "\n";
    }
}