HackerRank C++ For Loop

For each integer n in the interval [a,b] :

If 1<=n<=9, then print the English representation of it in lowercase. That is "one" for 1 , "two" for 2 , and so on.
Else if n>9 and it is an even number, then print "even".
Else if n>9 and it is an odd number, then print "odd".

#include <cmath>
#include <cstdio>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
int main()
{
int num1,num2;
cin >> num1 >> num2;
string Arr1[9] = {"one","two","three","four","five","six","seven","eight","nine"};
for(int i =num1; i <= num2;i++)
{
if(i <= 9)
{
cout << Arr1[i-1] << endl;
}
else
{
if(i%2 ==0)
{
cout << "even" << endl;
}
else
{
cout << "odd" << endl;
}
}
}
return 0;
}