HackerRank C++ For Loop
For each integer n in the interval [a,b] :
If 1<=n<=9, then print the English representation of it in lowercase. That is "one" for 1 , "two" for 2 , and so on.
Else if n>9 and it is an even number, then print "even".
Else if n>9 and it is an odd number, then print "odd".
- #include <cmath>
- #include <cstdio>
- #include <vector>
- #include <iostream>
- #include <algorithm>
- using namespace std;
- int main()
- {
- int num1,num2;
- cin >> num1 >> num2;
- string Arr1[9] = {"one","two","three","four","five","six","seven","eight","nine"};
- for(int i =num1; i <= num2;i++)
- {
- if(i <= 9)
- {
- cout << Arr1[i-1] << endl;
- }
- else
- {
- if(i%2 ==0)
- {
- cout << "even" << endl;
- }
- else
- {
- cout << "odd" << endl;
- }
- }
- }
- return 0;
- }
