HackerRank C- For Loop in C

For each integer n in the interval [a,b] (given as input) :

If 1<=n<=9, then print the English representation of it in lowercase. That is "one" for 1, "two" for 1 , and so on.
Else if n>9 and it is an even number, then print "even".
Else if n>9 and it is an odd number, then print "odd".

#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>



int main() 
{
    int a, b;
    int n=0;
    scanf("%d\n%d", &a, &b);
  	for(n=a;n<=b;n++)
    {
    if(n==1)
    {
        printf("one\n");
    }
    if(n==2)
    {
        printf("two\n");
    }
    if(n==3)
    {
        printf("three\n");
    }
    if(n==4)
    {
        printf("four\n");
    }
    if(n==5)
    {
        printf("five\n");
    }
    if(n==6)
    {
        printf("six\n");
    }
    if(n==7)
    {
        printf("seven\n");
    }
    if(n==8)
    {
        printf("eight\n");
    }
    if(n==9)
    {
        printf("nine\n");
    }
     if(n>9)
    {
       if(n%2==0)
       {
           printf("even\n");
       }
       else {
       printf("odd\n");
       }    
    }

      }
    return 0;
}