HackerRank C- Printing Pattern using Loops
In this problem, you need to print the pattern of the following form containing the numbers from 1 to n.
- #include <stdio.h>
- #include <string.h>
- #include <math.h>
- #include <stdlib.h>
-
- int main()
- {
-
- int n;
- scanf("%d", &n);
- int len = n*2 - 1;
- for(int i=0;i<len;i++){
- for(int j=0;j<len;j++){
- int min = i < j ? i : j;
- min = min < len-i ? min : len-i-1;
- min = min < len-j-1 ? min : len-j-1;
- printf("%d ", n-min);
- }
- printf("\n");
- }
- return 0;
- }
