HackerRank Java- Datatypes
Given an input integer, you must determine which primitive data types are capable of properly storing that input.
To get you started, a portion of the solution is provided for you in the editor.
- import java.util.*;
- import java.io.*;
-
-
-
- class Solution {
- public static void main(String[] args) {
- Scanner scan = new Scanner(System.in);
- int t = scan.nextInt();
- for (int i = 0; i < t; i++) {
- try {
- long x = scan.nextLong();
- System.out.println(x + " can be fitted in:");
- if (x >= Byte.MIN_VALUE && x <= Byte.MAX_VALUE) {
- System.out.println("* byte");
- }
- if (x >= Short.MIN_VALUE && x <= Short.MAX_VALUE) {
- System.out.println("* short");
- }
- if (x >= Integer.MIN_VALUE && x <= Integer.MAX_VALUE) {
- System.out.println("* int");
- }
- if (x >= Long.MIN_VALUE && x <= Long.MAX_VALUE) {
- System.out.println("* long");
- }
- } catch (Exception e) {
- System.out.println(scan.next() + " can't be fitted anywhere.");
- }
- }
- scan.close();
- }
- }