HackerRank Java- Exception Handling (Try-catch)




Java has built-in mechanism to handle exceptions. Using the try statement we can test a block of code for errors. The catch block contains the code that says what to do if exception occurs.

This problem will test your knowledge on try-catch block.

You will be given two integers x and y as input, you have to compute x/y. If x and y are not 32 bit signed integers or if is zero, exception will occur and you have to report it. Read sample Input/Output to know what to report in case of exceptions.



  1. import java.util.*;
  2. public class Solution {
  3. public static void main(String[] args) {
  4. Scanner scan = new Scanner(System.in);
  5. try {
  6. int x = scan.nextInt();
  7. int y = scan.nextInt();
  8. System.out.println(x / y);
  9. } catch (InputMismatchException e) {
  10. System.out.println(e.getClass().getName());
  11. } catch (ArithmeticException e) {
  12. System.out.println(e.getClass().getName() + ": / by zero");
  13. }
  14. }
  15. }




codesadda.com

Codesadda.com is your home of programming solutions, tutorials, video tutorials and much more. Sign Up for our weekly newsletter to get update about new content.

Like us on Facebook | Connect with us on LinkedIn | Subscribe our Channel on Youtube