HackerRank Java- Exception Handling (Try-catch)

Java has built-in mechanism to handle exceptions. Using the try statement we can test a block of code for errors. The catch block contains the code that says what to do if exception occurs.

This problem will test your knowledge on try-catch block.

You will be given two integers x and y as input, you have to compute x/y. If x and y are not 32 bit signed integers or if is zero, exception will occur and you have to report it. Read sample Input/Output to know what to report in case of exceptions.

import java.util.*;

public class Solution {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        try {
            int x = scan.nextInt();
            int y = scan.nextInt();
            System.out.println(x / y);
        } catch (InputMismatchException e) {
            System.out.println(e.getClass().getName());
        } catch (ArithmeticException e) {
            System.out.println(e.getClass().getName() + ": / by zero");
        }
    }
}