HackerRank Java- Exception Handling (Try-catch)
Java has built-in mechanism to handle exceptions. Using the try statement we can test a block of code for errors. The catch block contains the code that says what to do if exception occurs.
This problem will test your knowledge on try-catch block.
You will be given two integers x and y as input, you have to compute x/y. If x and y are not 32 bit signed integers or if is zero, exception will occur and you have to report it. Read sample Input/Output to know what to report in case of exceptions.
- import java.util.*;
-
- public class Solution {
-
- public static void main(String[] args) {
- Scanner scan = new Scanner(System.in);
- try {
- int x = scan.nextInt();
- int y = scan.nextInt();
- System.out.println(x / y);
- } catch (InputMismatchException e) {
- System.out.println(e.getClass().getName());
- } catch (ArithmeticException e) {
- System.out.println(e.getClass().getName() + ": / by zero");
- }
- }
- }
