Java Day 23: BST Level-Order Traversal
A level-order traversal, also known as a breadth-first search, visits each level of a tree's nodes from left to right, top to bottom. You are given a pointer, root , pointing to the root of a binary search tree. Complete the levelOrder function provided in your editor so that it prints the level-order traversal of the binary search tree.
Hint: You'll find a queue helpful in completing this challenge.
- import java.io.*;
- import java.util.*;
- class Node{
- Node left,right;
- int data;
- Node(int data){
- this.data=data;
- left=right=null;
- }
- }
- class Solution{
-
- public static void levelOrder(Node root) {
- Queue<Node> queue = new LinkedList<>();
- queue.add(root);
-
- while (!queue.isEmpty()) {
- Node curr = queue.remove();
- System.out.print(curr.data + " ");
-
- if (curr.left != null) queue.add(curr.left);
- if (curr.right != null) queue.add(curr.right);
- }
- }
-
- public static Node insert(Node root,int data){
- if(root==null){
- return new Node(data);
- }
- else{
- Node cur;
- if(data<=root.data){
- cur=insert(root.left,data);
- root.left=cur;
- }
- else{
- cur=insert(root.right,data);
- root.right=cur;
- }
- return root;
- }
- }
- public static void main(String args[]){
- Scanner sc=new Scanner(System.in);
- int T=sc.nextInt();
- Node root=null;
- while(T-->0){
- int data=sc.nextInt();
- root=insert(root,data);
- }
- levelOrder(root);
- }
- }
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