Python Day 24: More Linked Lists
A Node class is provided for you in the editor. A Node object has an integer data field, data, and a Node instance pointer, next, pointing to another node (i.e.: the next node in a list).
A removeDuplicates function is declared in your editor, which takes a pointer to the head node of a linked list as a parameter. Complete removeDuplicates so that it deletes any duplicate nodes from the list and returns the head of the updated list.
Note: The head+ pointer may be null, indicating that the list is empty. Be sure to reset your next pointer when performing deletions to avoid breaking the list.
- class Node:
- def __init__(self,data):
- self.data = data
- self.next = None
- class Solution:
- def insert(self,head,data):
- p = Node(data)
- if head==None:
- head=p
- elif head.next==None:
- head.next=p
- else:
- start=head
- while(start.next!=None):
- start=start.next
- start.next=p
- return head
- def display(self,head):
- current = head
- while current:
- print(current.data,end=' ')
- current = current.next
-
- def removeDuplicates(self,head):
- #Write your code here
- node = head
-
- while node:
- if node.next:
- if node.data == node.next.data:
- node.next = node.next.next
- continue
-
- node = node.next
-
- return head
-
- mylist= Solution()
- T=int(input())
- head=None
- for i in range(T):
- data=int(input())
- head=mylist.insert(head,data)
- head=mylist.removeDuplicates(head)
- mylist.display(head);
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